Example 1
With k = 200 N/m and an extension of 10 cm, the spring stores 1 J.
A deformed spring stores elastic potential energy. Because extension is squared, doubling the deformation multiplies the stored energy by four.
With k = 200 N/m and an extension of 10 cm, the spring stores 1 J.
A spring storing 4 J at 20 cm has k = 200 N/m.